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By Willy M Sansen

This ebook is entitled Analog layout necessities since it comprises all subject matters of value to the analog clothier that are necessary to receive enough insights to do an intensive activity.

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Additional info for Analog Design Essentials (The Springer International Series in Engineering and Computer Science)

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We will use this simple circuit to convert current to voltage. 0218 If we add a small-signal current to the DC current, then we find the small-signal equivalent circuit, as shown. The small-signal resistance r is then 1/g in pards m allel with the transistor output resistance r . Since DS the latter one is always significantly larger than 1/g , m it can be simplified to 1/g m itself. The small-signal resistance of a diode connected MOST is thus always 1/g , m very much as for a bipolar transistor.

M DS This increased output resistance will be used to increase the gain! The input capacitance is decreased by the feedback. The larger the resistor R , the smaller the S input capacitance. If R were replaced by a DC current source, the input capacitance would be S negligible. Actually, the gain would be negligible as well. This is a source follower, as discussed later. 58 Chapter #2 The main problem of R is its noise. This is why in low-noise RF circuits, an inductor is S used instead. 0215 Inductors and capacitances do not give noise, at least not as long as their series loss resistance is zero.

As this factor b is never accurately known, this resistor r is m p not well known either. It certainly depends on the current. 1 mA and a b of about 100, this resistor is about 26 kV. This is a rather low value and imprecise. It cannot be allowed to play an important role in high-precision circuitry. Finally, a Base resistor r has to be added in series with the input. It is an ohmic resistance B which is mainly the resistance of p-Base region between the Emitter side and the Base contact. 0177 As a bipolar transistor is built up with many junctions, it contains many junction capacitances.

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